I am currently looking to get two JL 8w3v3's and i was wondering about the recommended volume size. On crutchfield it says the recommended sealed box volume for one sub is .3 cu/ft. Does that mean the total inside volume of the box should be .3 cu/ft or does it mean that total volume minus the volume taken up by the sub should be .3 cu/ft? Thanks in advance.

 

8W3v3's need .03cu feet. That would be the total volume inside the box. If there is less airspace, the sub will hit harder if there is more it will sound weak. Just a suggestion but 2 8"s won't make for much power you should go for the 10's or one 12"W6.

 

Just for clarification, does that mean i dont have to account for the volume of the sub?

 

look for the Displacement figure on JLaudio.com and take that into the equation.....

 

Actually the .03 cu ft is the displacement of the speaker. You will need at least .3 cu ft of clear open airspace. So add the .3 and the .03 together. And make sure that is the inside dimensions of the box are your .33 cu ft.

 

No, you SHOULD account for the displacement volume of the sub itself and have .3 cubic feet for each sub after factoring in the sub's displacement volume.

 

Yeh should have made that more clear, .33 cu. ft on the inside each speaker.

 

 

Haha, thanks guys! I appreciate the help.

 

I disagree with this statement. If you use a larger enclosure, your sub will play louder and lower easier, but will lose compliance faster and bottom out quicker. Less volume will keep compliance lower down, but will require more power to obtain equal volume output.

 

You sir are correct!

 

you shouldn't.